C++：检查一个向量中的元素是否大于另一个具有相同索引的元素的有效方法？

#include <iostream>
#include <vector>
#include <algorithm>

bool all_elements_greater(const std::vector<int>& vec1, const std::vector<int>& vec2) {
    // 检查两个向量是否大小相同
    if (vec1.size() != vec2.size()) {
        throw std::invalid_argument("Vectors must be of the same size");
    }

    // 使用std::all_of算法检查每个元素
    return std::all_of(vec1.begin(), vec1.end(), [&](int value) {
        int index = &value - &vec1[0]; // 获取当前元素的索引
        return value > vec2[index];
    });
}

int main() {
    std::vector<int> vec1 = {5, 10, 15};
    std::vector<int> vec2 = {3, 9, 14};

    try {
        if (all_elements_greater(vec1, vec2)) {
            std::cout << "All elements in vec1 are greater than corresponding elements in vec2." << std::endl;
        } else {
            std::cout << "Not all elements in vec1 are greater than corresponding elements in vec2." << std::endl;
        }
    } catch (const std::invalid_argument& e) {
        std::cerr << e.what() << std::endl;
    }

    return 0;
}