C语言中两个矩阵的和与积(含函数)

#include <stdio.h>

#define ROWS 3
#define COLS 3

void matrixSum(int A[ROWS][COLS], int B[ROWS][COLS], int C[ROWS][COLS]) {
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            C[i][j] = A[i][j] + B[i][j];
        }
    }
}

int main() {
    int A[ROWS][COLS] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
    int B[ROWS][COLS] = {{9, 8, 7}, {6, 5, 4}, {3, 2, 1}};
    int C[ROWS][COLS];

    matrixSum(A, B, C);

    printf("Matrix C (Sum):\n");
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            printf("%d ", C[i][j]);
        }
        printf("\n");
    }

    return 0;
}

#include <stdio.h>

#define ROWS_A 2
#define COLS_A 3
#define ROWS_B 3
#define COLS_B 2

void matrixProduct(int A[ROWS_A][COLS_A], int B[ROWS_B][COLS_B], int C[ROWS_A][COLS_B]) {
    for (int i = 0; i < ROWS_A; i++) {
        for (int j = 0; j < COLS_B; j++) {
            C[i][j] = 0;
            for (int k = 0; k < COLS_A; k++) {
                C[i][j] += A[i][k] * B[k][j];
            }
        }
    }
}

int main() {
    int A[ROWS_A][COLS_A] = {{1, 2, 3}, {4, 5, 6}};
    int B[ROWS_B][COLS_B] = {{7, 8}, {9, 10}, {11, 12}};
    int C[ROWS_A][COLS_B];

    matrixProduct(A, B, C);

    printf("Matrix C (Product):\n");
    for (int i = 0; i < ROWS_A; i++) {
        for (int j = 0; j < COLS_B; j++) {
            printf("%d ", C[i][j]);
        }
        printf("\n");
    }

    return 0;
}