+-------------+-----------+---------+-------++----SELECT right_id, COUNT(right_id) AS right_count FROM `user_count` GROUP BY right_id;
SELECT left_id AS meb_idleft_id) AS active_left_count FROM `user_count` WHERE active = 1 GROUP
我有另一个表mebs (在SQLAlchemy中映射为MEB)。如果我尝试执行以下命令 filter(Property.PostCode == MEB.PostCode).\我得到了
InvalidRequestError: This operation requires only one Table or entity be specified as
) FROM coureurs NATURAL JOIN resultats NATURAL JOIN courses NATURAL JOIN categories WHERE classe='4èmeB' AND moyenne IS NOT NULL),'4èmeB');
我在那里用了三个表格,它们是类,跑步者,结果(成绩),课程(赛跑),类别。
*,t.left_id AS meb_id,(CAST(t.pair AS UNSIGNED) - IFNULL(p.pair,0)) AS pair FROM (SELECT left_id,
(CASEWHEN ((SELECT COUNT(meb_id) FROM user_count WHERE left_id=u.left_id AND active = 1 AND join_date <='1442255400000') >= (SELECT COUNT(meb_id) FROM user_cou