Python cv2 90:90宽高比矩形到裁剪图像

import cv2

def crop_to_aspect_ratio(image, target_aspect_ratio=(90, 90)):
    height, width = image.shape[:2]
    target_width, target_height = target_aspect_ratio
    
    # 计算原始图像的宽高比
    original_aspect_ratio = width / height
    
    # 确定裁剪区域的起始点和大小
    if original_aspect_ratio > target_aspect_ratio[0] / target_aspect_ratio[1]:
        # 图像太宽，需要裁剪宽度
        new_width = int(height * target_aspect_ratio[0] / target_aspect_ratio[1])
        x = (width - new_width) // 2
        y = 0
        crop_image = image[y:y+height, x:x+new_width]
    else:
        # 图像太高，需要裁剪高度
        new_height = int(width * target_aspect_ratio[1] / target_aspect_ratio[0])
        x = 0
        y = (height - new_height) // 2
        crop_image = image[y:y+new_height, x:x+width]
    
    return crop_image

# 读取图像
image = cv2.imread('path_to_your_image.jpg')

# 裁剪图像
cropped_image = crop_to_aspect_ratio(image)

# 显示结果
cv2.imshow('Cropped Image', cropped_image)
cv2.waitKey(0)
cv2.destroyAllWindows()