如果我将这条语句复制到MySQLPHPAdmin中,得到的错误是You have an error in your SQL syntax; check the manual that correspondsto your MySQL server version for the right syntax to use near '1update page SET RegionId = 1 WHEREupdate page SET RegionId = 2 WHERE (RegionId = -1 or RegionId = -3) and De
从MySQL查询中选择一行的PHP是什么?也就是说,你是通过唯一的ID (你知道只有一行匹配你的请求)来挑选一些东西,并且只想得到那个值。你还需要使用while循环和mysql_fetch_row吗?$query = "SELECT name,age FROM people WHERE uid = '2'";
// what php is
我是一个PHP新手,我试图找出将下面代码中的random_num放入PHP变量的最佳方法。random_num WHERE random_num NOT IN (SELECT random_num FROM numbers_mst)对不起,如果这很简单的话,我尝试过各种语法变体,并在谷歌上搜索过,但我只能找到如何将行结果放入变量中……
我正在尝试执行以下查询。update share set holder = 22 where SHARE_ID IN (select SHARE_ID from SHARE WHERE holder=1 LIMIT 10)#1235 - This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'