python pandas如何在精确id连续出现n次时更改值

import pandas as pd

data = {'id': [1, 1, 1, 2, 2, 3, 4, 4, 4, 4, 5]}
df = pd.DataFrame(data)

df['count'] = df.groupby('id').cumcount() + 1

n = 3  # 连续出现n次
df.loc[df['count'] >= n, 'id'] = 100  # 更改对应的id值为100

import pandas as pd

# 创建DataFrame
data = {'id': [1, 1, 1, 2, 2, 3, 4, 4, 4, 4, 5]}
df = pd.DataFrame(data)

# 计算连续出现次数
df['count'] = df.groupby('id').cumcount() + 1

# 更改值
n = 3  # 连续出现n次
df.loc[df['count'] >= n, 'id'] = 100  # 更改对应的id值为100

print(df)

    id  count
0    1      1
1    1      2
2    1      3
3    2      1
4    2      2
5    3      1
6  100      1
7  100      2
8  100      3
9    4      1
10   5      1