python:如何在代码中自动运行为一组三个列表选择所有选项以生成所有置换

def generate_permutations(list1, list2, list3):
    if len(list1) == 0:
        return [[]]
    
    permutations = []
    for i in range(len(list1)):
        current = list1[i]
        remaining1 = list1[:i] + list1[i+1:]
        
        for j in range(len(list2)):
            current2 = list2[j]
            remaining2 = list2[:j] + list2[j+1:]
            
            for k in range(len(list3)):
                current3 = list3[k]
                remaining3 = list3[:k] + list3[k+1:]
                
                sub_permutations = generate_permutations(remaining1, remaining2, remaining3)
                for sub_permutation in sub_permutations:
                    permutation = [current, current2, current3] + sub_permutation
                    permutations.append(permutation)
    
    return permutations

# 示例用法
list1 = [1, 2, 3]
list2 = ['a', 'b', 'c']
list3 = ['x', 'y', 'z']

permutations = generate_permutations(list1, list2, list3)
for permutation in permutations:
    print(permutation)