toXML在JsonParser中处于什么位置，为什么该方法不可用？

import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.dataformat.xml.XmlMapper;

public class JsonToXmlExample {
    public static void main(String[] args) throws Exception {
        String jsonString = "{\"name\":\"John\", \"age\":30}";

        // 解析 JSON 字符串
        ObjectMapper jsonMapper = new ObjectMapper();
        JsonNode jsonNode = jsonMapper.readTree(jsonString);

        // 将 JSON 转换为 XML
        XmlMapper xmlMapper = new XmlMapper();
        String xmlString = xmlMapper.writeValueAsString(jsonNode);

        System.out.println(xmlString);
    }
}