问Spring REST JUnit 4
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Stack Overflow用户

提问于 2012-10-30 13:05:57

回答 2查看 663关注 0票数 1

我有一个spring控制器，它有多个spring bean依赖项(自动连接的服务)。每个服务也有很少的spring bean依赖项(自动连接的daos)。例如，控制器登录方式：

@Controller
@RequestMapping("/")
public class ClientAccessController extends BaseController {

    @Autowired
    IFileService fileService;

    @Autowired
    MidTierService midTierService;

    /**
     * Used to handle client login requests
     * Works as a proxy to MID tier server
     *
     * @param request LoginRequest(userLogin, userPassword, compId, installGuid)
     * @return LoginResponse (token)
     * @throws Exception
     */
    @RequestMapping(method = RequestMethod.POST, value = "/login", headers = "Content-   type=application/json")
    public ResponseEntity<LoginResponse> login(@RequestBody LoginRequest request) throws Exception {

        log.info("LOGIN REQUEST [ " + request.toString() + " ]");

        String token = midTierService.authenticateNativeClient(request.getLogin(), request.getPassword(), request.getGuId(),
                request.getCompid().toString());
        LoginResponse response = new LoginResponse(token);

        HttpHeaders httpHeaders = new HttpHeaders();
        httpHeaders.setContentType(MediaType.APPLICATION_JSON);

        ResponseEntity<LoginResponse> responseEntity = new ResponseEntity<>(response, HttpStatus.OK);

        log.info("LOGIN RESPONSE [ " + response.toString());

        return responseEntity;
    }

我正在尝试只为控制器ClienAccessController编写JUnit测试。但是当我在测试类中自动连接ClientAccessController时，spring会尝试为所有控制器依赖项和所有嵌套依赖项(daos等)创建beans，但我真的不需要它们，只需要MidTierService。那么，我应该怎么做才能排除嵌套的bean初始化，并且只在测试类中使用我需要的东西呢？

spring

rest

spring-mvc

junit

回答 2

Stack Overflow用户

回答已采纳

发布于 2012-10-30 13:09:22

Spring允许不止一种方式访问@Autowired成员。对我来说，更好的方法(从可测试性的角度来看)是对构造函数进行@Autowired。因此，我将为ClientAccessController创建一个如下所示的构造函数：

@Autowired
public ClientAccessController(final IFileService fileService, final MidTierService midTierService) {
    this.fileService = fileService;
    this.midTierService = midTierService;
}

如果您的自动装配有点复杂(因为它使用@Qualifier或@Value)，那么可以使用参数注释完成更多工作。

@Autowired
public ClientAccessController(@Qualifier("myFileService") final IFileService fileService,
       @Qualifier("myMidTierService") final MidTierService midTierService) {
    this.fileService = fileService;
    this.midTierService = midTierService;
}

这样，您就可以很容易地使用模拟对象或存根来设置此类以进行测试。

@Test
public void testClientAccessController() {
    final IFileService mockFileService = Mockito.mock(IFileService.class);
    final MidTierService mockMidTierService = Mockito.mock(MidTierService.class);
    final ClientAccessController controller = new ClientAccessController(mockFileService, mockMidTierService);
    //test it
}

票数 1

Stack Overflow用户

发布于 2013-04-08 17:01:29

我没有使用所有依赖项作为参数来创建构造函数，而是为每个依赖项创建了一个set方法。这样，我就可以在测试中模拟这些依赖项，并用setter注入它们。因此，测试的结果如下：

@Test
public void testClientAccessController() {
    final IFileService mockFileService = Mockito.mock(IFileService.class);
    final MidTierService mockMidTierService = Mockito.mock(MidTierService.class);
    final ClientAccessController controller = new ClientAccessController();

    controller.setFileService(mockFileService);
    controller.setMidTierService(mockMidTierService);
    //test it
}