问在bash中将csv的单列水平拆分为多个BASH中的较小csv文件

EN

$ ls 
file

$ cat file 
111 
222 
333 
444 
555 
666 
777 
888

$ awk '{print $0 > ("output"i+1".csv")}!(NR%4){i++}' file

$ ls
file  output1.csv  output2.csv

$ cat output1.csv 
111 
222 
333 
444 

$ cat output2.csv 
555 
666 
777 
888

$ awk '{print NR%4,$0}' file
1 111
2 222
3 333
0 444
1 555
2 666
3 777
0 888

$ awk '{print NR%4,$0,"output"i+1".csv"}!(NR%4){i++}' file
1 111 output1.csv
2 222 output1.csv
3 333 output1.csv
0 444 output1.csv
1 555 output2.csv
2 666 output2.csv
3 777 output2.csv
0 888 output2.csv

split -nl/2 input output

-n, --number=CHUNKS
              generate CHUNKS output files.  See below
 CHUNKS may be: N       split into N files based on size of input K/N     output Kth of N to stdout l/N     split into N  files  without  splitting  lines  l/K/N
       output Kth of N to stdout without splitting lines r/N     like 'l' but use round robin distribution r/K/N   likewise but only output Kth of N to stdout

>cat my.csv
111
222
333
444
555
666
777
888 
>cat my.csv | xargs -n 1 -i echo \{\}, | xargs -n 4 
111, 222, 333, 444,
555, 666, 777, 888,