问ruby on rails:未定义的方法`_path‘
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Stack Overflow用户

提问于 2018-01-27 20:44:03

回答 2查看 912关注 0票数 1

当我试图创建一个新房间时，我从视图的第7行得到错误：

undefined method `rooms_path' for #<#<Class:0x007fb46b5db2a0>:0x007fb46b5d9ec8>

我有点困惑为什么我会得到这个错误。我已经在Room和Facility之间建立了一种关系，即每个设施都有许多房间。工具部分的工作没有bug，我已经能够创建/编辑/显示工具。

视图(视图/房间/new.html.erb)

<div class="panel panel-default">
  <div class="panel-heading">
    Create your beautiful room
  </div>
  <div class="panel-body">
    <div class="container">
      <%= form_for @room do |f| %>
        <div class="form-group">
          <label>Name</label>
          <%=f.text_field :room_name, placeholder: "What is the name of the room?", class: "form-control", required: true%>
        </div>

        <div><%= f.submit "Create This Room", class: "btn btn-normal" %></div>

      <%end%>
    </div>
  </div>
</div>

我的房间模型( model /room.rb)：

class Room < ApplicationRecord
  belongs_to :facility

  validates :room_type, presence: true
  validates :room_name, presence: true
end

My Facility model (models/facility.rb)：

class Facility < ApplicationRecord
  belongs_to :user
  has_many :photos
  has_many :rooms

  validates :facility_name, presence: true
  validates :address, presence: true
  validates :license, presence: true
  validates :phone, presence: true

  def cover_photo(size)
    if self.photos.length > 0
      self.photos[0].image.url(size)
    else
      "blank.jpg"
    end
  end
  
end

我的房间控制器(Controller/RoomsControler.rb)

class RoomsController < ApplicationController
  before_action :set_room, except: [:index, :new, :create]
  
  def index
    @facility = Facility.find(params[:facility_id])
    @rooms = @facility.rooms
  end

  def new
    @facility = Facility.find(params[:facility_id])
    @room = @facility.rooms.build
  end
 end

路由(routes.rb)

Rails.application.routes.draw do
  devise_for :users,
              path: '',
              path_names: {sign_in: 'login', sign_out: 'logout', edit: 'profile', sign_up: 'registration'},
              controllers: {omniauth_callbacks: 'omniauth_callbacks', registrations: 'registrations'}

  resources :users, only: [:show]
  resources :facilities, except: [:edit] do
    member  do
      get 'listing'
      get 'pricing'
      get 'features'
      get 'services'
      get 'types_care'
      get 'photo_upload'
      get 'room_upload'
    end

    resources :rooms, except: [:edit] do
      member  do
        get 'listing'
        get 'pricing'
        get 'photo_upload'
      end
    end

    resources :photos, only: [:create, :destroy]
  end
end

我已经坚持了几天了，真的很感谢你的帮助:)提前谢谢！

ruby-on-rails

ruby

model-view-controller

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回答 2

Stack Overflow用户

发布于 2018-01-28 01:43:58

form_for基于@room的类生成url，不包含外部资源。因此，您必须使用以下语句显式地告诉Rails执行此操作：

<%= form_for [@room.facility, @room] do |f| %>

票数 0

Stack Overflow用户

发布于 2018-01-28 09:48:12

由于路径是嵌套的，因此请为form_for选择以下任一选项，而不是<%= form_for @room do |f| %>

<%= form_for @room, url: [@room.facility, @room] do |f| %>

<%= form_for @room, url: [:facility, @room] do |f| %>

<%= form_for [@room.facility, @room] do |f| %>

<%= form_for [:facility, @room] do |f| %>