关于将迭代器传递给函数的C++尴尬问题

#include <iostream>
#include <vector>

void remove_even_numbers(std::vector<int>& vec) {
    for (auto it = vec.begin(); it != vec.end(); ) {
        if (*it % 2 == 0) {
            it = vec.erase(it); // 使用erase返回的新迭代器
        } else {
            ++it;
        }
    }
}

int main() {
    std::vector<int> numbers = {1, 2, 3, 4, 5};
    remove_even_numbers(numbers);
    for (int num : numbers) {
        std::cout << num << " ";
    }
    return 0;
}

#include <iostream>
#include <vector>
#include <memory>

void print_elements(const std::vector<int>& vec, std::shared_ptr<std::vector<int>::const_iterator> it) {
    while (*it != vec.end()) {
        std::cout << **it << " ";
        ++(*it);
    }
}

int main() {
    std::vector<int> numbers = {1, 2, 3, 4, 5};
    auto it = std::make_shared<std::vector<int>::const_iterator>(numbers.begin());
    print_elements(numbers, it);
    return 0;
}