如何将具有相同ID的行合并到列表中

def merge_rows_by_id(rows):
    merged_list = []
    grouped_rows = {}

    # 分组
    for row in rows:
        row_id = row['ID']
        if row_id not in grouped_rows:
            grouped_rows[row_id] = []

        grouped_rows[row_id].append(row)

    # 合并
    for id, rows in grouped_rows.items():
        merged_row = {}
        for row in rows:
            merged_row.update(row)
        merged_list.append(merged_row)

    return merged_list

# 示例数据
rows = [
    {'ID': 1, 'Name': 'Alice', 'Age': 25},
    {'ID': 2, 'Name': 'Bob', 'Age': 30},
    {'ID': 1, 'Name': 'Charlie', 'Age': 35},
    {'ID': 3, 'Name': 'David', 'Age': 40},
]

# 合并行
merged_rows = merge_rows_by_id(rows)

# 输出结果
for row in merged_rows:
    print(row)

{'ID': 1, 'Name': 'Charlie', 'Age': 35}
{'ID': 2, 'Name': 'Bob', 'Age': 30}
{'ID': 3, 'Name': 'David', 'Age': 40}