字符串列表中最常见的部分字符串匹配

def most_common_substring(strings):
    substring_count = {}
    
    # 遍历字符串列表
    for string in strings:
        # 拆分字符串为所有可能的子字符串
        for i in range(len(string)):
            for j in range(i+1, len(string)+1):
                substring = string[i:j]
                
                # 将子字符串存储在哈希表中，并记录出现次数
                if substring in substring_count:
                    substring_count[substring] += 1
                else:
                    substring_count[substring] = 1
    
    # 找到出现次数最多的子字符串
    max_count = 0
    most_common_substring = ""
    for substring, count in substring_count.items():
        if count > max_count:
            max_count = count
            most_common_substring = substring
    
    return most_common_substring

# 示例用法
strings = ["abcde", "abcfgh", "abcd", "abcf", "abc"]
result = most_common_substring(strings)
print(result)