python趣味玩法

小闫同学啊

发布于 2019-07-18 16:21:03

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发布于 2019-07-18 16:21:03

文章被收录于专栏：小闫笔记小闫笔记

此文章代码均由好友彭老板提供，彭老板个人主页： https://segmentfault.com/u/mixtualyue

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Always make a total effort, even when the odds are against you.

即使可能性很大，也要付出全部努力。

小闫语录：

大壮曾唱到：“在一瞬间，有一百万种可能。”即使有把握的一件事，结果仍是未知数，只有完成那一刻，才是定数。切莫轻视。

樱花树

先来看一下效果：

然后贴出源码：

import turtle
import random
from turtle import *
from time import sleep

t = turtle.Turtle()
w = turtle.Screen()

def tree(branchLen, t):
    if branchLen > 3:
        if 8 <= branchLen <= 12:
            if random.randint(0, 2) == 0:
                t.color('snow')
            else:
                t.color('lightcoral')
            t.pensize(branchLen / 3)
        elif branchLen < 8:
            if random.randint(0, 1) == 0:
                t.color('snow')
            else:
                t.color('lightcoral')
            t.pensize(branchLen / 2)
        else:
            t.color('sienna')
            t.pensize(branchLen / 10)

        t.forward(branchLen)
        a = 1.5 * random.random()
        t.right(20*a)
        b = 1.5 * random.random()
        tree(branchLen-10*b, t)
        t.left(40*a)
        tree(branchLen-10*b, t)
        t.right(20*a)
        t.up()
        t.backward(branchLen)
        t.down()


def petal(m, t):  # 树下花瓣
    for i in range(m):
        a = 200 - 400 * random.random()
        b = 10 - 20 * random.random()
        t.up()
        t.forward(b)
        t.left(90)
        t.forward(a)
        t.down()
        t.color("lightcoral")
        t.circle(1)
        t.up()
        t.backward(a)
        t.right(90)
        t.backward(b)


def main():
    t = turtle.Turtle()
    myWin = turtle.Screen()
    getscreen().tracer(5, 0)
    turtle.screensize(bg='wheat')
    t.left(90)
    t.up()
    t.backward(150)
    t.down()
    t.color('sienna')
    tree(60, t)
    petal(100, t)

    myWin.exitonclick()


main()

深沉的树

先来看一下效果：

然后贴出源码：

from turtle import *
from random import *
from math import *


def tree(n, l):
    pd()
    t = cos(radians(heading() + 45)) / 8 + 0.25

    pencolor(t, t, t)
    pensize(n / 4)
    forward(l)
    if n > 0:
        b = random() * 15 + 10
        c = random() * 15 + 10
        d = l * (random() * 0.35 + 0.6)
        right(b)
        tree(n - 1, d)
        left(b + c)
        tree(n - 1, d)
        right(c)
    else:
        right(90)
        n = cos(radians(heading() - 45)) / 4 + 0.5
        pencolor(n, n, n)
        circle(2)
        left(90)
    pu()
    backward(l)


bgcolor(0.5, 0.5, 0.5)
ht()
speed(0)
tracer(0, 0)
left(90)
pu()
backward(300)
tree(13, 100)
done()