问如何从XML文件中自动获取相同类型的每个对象？
EN

Stack Overflow用户

提问于 2021-07-29 16:07:29

回答 1查看 116关注 0票数 0

我正在尝试将XML文件解析为TXT文件。这是我的XML文件的样子：

<annotation>
  <folder>training</folder>
  <filename>106310488.jpg</filename>
  <source>
    <database>synthetic initialization</database>
    <annotation>PASCAL VOC2007</annotation>
    <image>synthetic</image>
    <flickrid>none</flickrid>
  </source>
  <owner>
    <flickrid>none</flickrid>
    <name>none</name>
  </owner>
  <size>
    <width>1024</width>
    <height>681</height>
    <depth>3</depth>
  </size>
  <segmented>0</segmented>
  <object>
    <name>shell</name>
    <pose>Unspecified</pose>
    <truncated>0</truncated>
    <difficult>0</difficult>
    <bndbox>
      <xmin>234</xmin>
      <ymin>293</ymin>
      <xmax>281</xmax>
      <ymax>340</ymax>
    </bndbox>
 </object>
 <object>
    <name>shell</name>
    <pose>Unspecified</pose>
    <truncated>0</truncated>
    <difficult>0</difficult>
    <bndbox>
      <xmin>504</xmin>
      <ymin>302</ymin>
      <xmax>551</xmax>
      <ymax>349</ymax>
    </bndbox>
  </object>
  <object>
    <name>shell</name>
    <pose>Unspecified</pose>
    <truncated>0</truncated>
    <difficult>0</difficult>
    <bndbox>
      <xmin>776</xmin>
      <ymin>302</ymin>
      <xmax>823</xmax>
      <ymax>349</ymax>
    </bndbox>
  </object>
</annotation>

我感兴趣的信息在<object>中。我想要得到<bndbox>中的<name>和所有东西。这些是数据集中对象的名称和边界框坐标。我不知道每个XML文件中的<bndbox>都有<object>条目，所以我想编写一个获取所有条目的逻辑。

到目前为止，我的逻辑所做的就是只获取和处理第一次出现的<object><bndbox></bndbox></object>。如果XML文件中有任何其他边界框坐标，我的代码将直接跳过它。我不想这样。下面是我的代码：

for annotations_file in annotations_dir:

  annotations = []
  milliseconds = int(time() * 1000)

  doc = ET.parse('/content/darknet/logorec/openlogo/Annotations/' + annotations_file) # Parsing the XML file
  
  new_annotations_file_name = annotations_file.split('.')[0] # Getting the name of the XML file without the file extension
  
  canvas = cv2.imread('/content/darknet/logorec/openlogo/JPEGImages/' + new_annotations_file_name + '.jpg') # Get the entire image
  
  canvas_shape = canvas.shape # Get the dimensions of the image
  
  root = doc.getroot() # Gets the root of the XML file
  
  annotations_box = root[6][4] # Gets the bounding box coordinates from the XML file

  class_name = root[6][0] # Name of the object within the bounding box
  class_name = class_name.text # Getting the text value

  for ant in annotations_box:
    annotations.append(ant.text) # Appending every sindle bounding box coordinate to an empty list
  
  ''' These are my annotations calculations for the YOLO model'''
  logo_shape_w = int(annotations[2]) - int(annotations[0])
  logo_shape_h = int(annotations[3]) - int(annotations[1])

  x1 = int(annotations[0]) # x1 = xmin
  y1 = int(annotations[3]) # y1 = ymax

  x2 = x1 + logo_shape_w
  y2 = y1 + logo_shape_h

  w = x2 - x1
  h = y2 - y1

  center_x = x1 + (w/2)
  center_y = y1 + (h/2)

  x = center_x / canvas_shape[0]
  y = center_y / canvas_shape[1]

  width = w / canvas_shape[0]
  height = h / canvas_shape[1]
  '''---------------------------------------------------------'''

python

xml

computer-vision

yolo

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回答 1

Stack Overflow用户

回答已采纳

发布于 2021-07-29 16:37:37

使用xpath解析XML可以遍历objList项。仅显示第一个项目

>>> from lxml import etree                       
>>> tree = etree.parse('test.xml')                                                                                                              
>>> objList = tree.xpath('//object')
>>> bnd = objList[0].xpath('name | bndbox/*')
>>> for e in bnd:
...     e.text
... 
'shell'
'234'
'293'
'281'
'340'

迭代所有对象

>>> for obj in objList:
...      bnd = obj.xpath('name | bndbox/*')
...      for e in bnd:
...          e.text
... 
'shell'
'234'
'293'
'281'
'340'
'shell'
'504'
'302'
'551'
'349'
'shell'
'776'
'302'
'823'