问阅读SpeechRecognitionEngine中的一个短语
EN

Stack Overflow用户

提问于 2022-07-29 14:37:08

回答 1查看 25关注 0票数 0

我正在使用SpeechRecognizer，看看它是否支持我正在设计的应用程序的特性。

下面的代码适用于单个单词。但是，分析一个短语有可能吗？我的应用程序不需要使用大的短语，只有3个或4个单词的短语。举个例子，我试图让这个应用程序看到有多个“单词”在被表达(尽管技术上它不是多个单词)。

    static void Main(string[] args)
    {

        // Create an in-process speech recognizer for the en-US locale.  
        using ( SpeechRecognitionEngine recognizer = new SpeechRecognitionEngine( new System.Globalization.CultureInfo("en-US")))
        {
            Choices c = new Choices();

            c.Add("one");
            c.Add("two");
            c.Add("three");
            c.Add("twenty");

            var gb = new GrammarBuilder(c);
            var g = new Grammar(gb);
            recognizer.LoadGrammar(g);

            // Add a handler for the speech recognized event.  
            recognizer.SpeechRecognized += new EventHandler<SpeechRecognizedEventArgs>(recognizer_SpeechRecognized);

            // Configure input to the speech recognizer.  
            recognizer.SetInputToDefaultAudioDevice();

            // Start asynchronous, continuous speech recognition.  
            recognizer.RecognizeAsync(RecognizeMode.Multiple);

            // Keep the console window open.  
            while (true)
            {
                Console.ReadLine();
            }
        }
    }

    // Handle the SpeechRecognized event.  
    static void recognizer_SpeechRecognized(object sender, SpeechRecognizedEventArgs e)
    {
        Console.WriteLine("Recognized text: " + e.Result.Text);
    }

我会说话，它会返回一，二，三和二十。但如果我说是二十一号，那就只有二十个了。

有没有一种方法来扩展多少个“音节”(我甚至不确定这里使用的术语)，它将分析？

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回答 1

Stack Overflow用户

回答已采纳

发布于 2022-07-30 07:00:59

答案是“是”/“否”，似乎没有办法使“21”合乎逻辑，所以我认为这将是一个限制，除非我另有指出。然而，在阅读MS文档的更多内容时，我发现如下：

    static Grammar CreateServicesGrammar(string grammarName)
    {

        // Create a grammar for finding services in different cities.  
        Choices services = new Choices(new string[] { "restaurants", "hotels", "gas stations" });
        Choices cities = new Choices(new string[] { "Seattle", "Boston", "Dallas" });

        GrammarBuilder findServices = new GrammarBuilder("Find");
        findServices.Append(services);
        findServices.Append("near");
        findServices.Append(cities);

        // Create a Grammar object from the GrammarBuilder. 
        Grammar servicesGrammar = new Grammar(findServices);
        servicesGrammar.Name = ("FindServices");
        return servicesGrammar;
    }