问如何确保一个系统通过局域网连接？
EN

Stack Overflow用户

提问于 2012-04-01 03:02:44

回答 2查看 1.7K关注 0票数 3

在我的Swing应用程序(使用Web-Start)中，我必须手动输入我想要访问应用程序的机器的IP地址，现在，在访问IP地址时，我要检查我输入的机器IP地址是否仅通过LAN (通过交换机，而不是路由器)连接到我的机器(充当本地服务器)。因为如果机器不在LAN中，它就不应该授予访问应用程序的权限。

我怎样才能做到这一点？

java

swing

networking

回答 2

Stack Overflow用户

回答已采纳

发布于 2012-04-01 06:17:44

据我了解您的问题，您需要检查输入到应用程序中的特定IP地址是否位于客户端主机的直接连接网络上。

如果是这样的话，那么使用普通ping将不适合您，因为ping将涉及数据包路由。所以就连路由器后面的主机也会回复。

作为解决办法，您可以在ping中添加‘-t1’参数，为ICMP数据包指定TTL，这样它们就不能通过路由器。

或者看看下面的示例，如果您希望这样的东西在java中实现(您应该根据您的需要采用它)：

public class IsAddressDirectlyConnected {

    private static class Network {
        int network;
        int mask;

        Network(int n, int m) {
            network = n;
            mask = m;
        }
    };

    // list of networks on interfaces of machine this code is being run on
    List<Network> mDirectlyAttachedNetworks = new ArrayList<Network>();

    private int addrBytesToInt(byte[] addr) {
        int addri = 0;
        for (int i = 0; i < addr.length; ++i)
            addri = (addri << 8) | ((int)addr[i] & 0xFF);        
        return addri;
    }

    private void collectLocalAddresses() {
        try {
            Enumeration<NetworkInterface> nifs = NetworkInterface.getNetworkInterfaces();

            while (nifs.hasMoreElements()) {
                NetworkInterface nif = nifs.nextElement();
                if (nif.isUp()) {
                    List<InterfaceAddress> ias = nif.getInterfaceAddresses();
                    for (InterfaceAddress ia : ias) {
                        InetAddress ina = ia.getAddress();
                        if (ina instanceof Inet4Address) {
                            int addri = addrBytesToInt(ina.getAddress());
                            int mask = -1 << (32 - ia.getNetworkPrefixLength());
                            addri &= mask;
                            mDirectlyAttachedNetworks.add(new Network(addri, mask));
                        }
                    }
                }
            }
        } catch (SocketException ex) {
            System.err.println("Socket i/o error: " + ex.getLocalizedMessage());
        }
    }

    public boolean isDirectlyAttachedAndReachable(InetAddress address) {
        int checkedAddr = addrBytesToInt(address.getAddress());
        try {
            if (!address.isReachable(1000))
                return false;
        } catch (IOException ex) {
            System.err.println("Failed to check reachability: " + ex.getLocalizedMessage());
            return false;
        }

        for (Network n : mDirectlyAttachedNetworks) {
            if ((checkedAddr & n.mask) == n.network)
                return true;
        }
        return false;
    }

    public IsAddressDirectlyConnected() {
        collectLocalAddresses();
    }

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        IsAddressDirectlyConnected iadc = new IsAddressDirectlyConnected();

        if (args.length == 1) {
            try {
                boolean check = iadc.isDirectlyAttachedAndReachable(Inet4Address.getByName(args[0]));
                System.out.println("Given IP is " + (check ? "" : "not ") + "on directly attached network " + (check ? "and " : "or not ")  + "reachable from local host.");
            } catch (UnknownHostException ex) {
                System.err.println("Failed to parse address: " + ex.getLocalizedMessage());
            }
        } else System.out.println("Specify address to check.");
    }
}

票数 4

Stack Overflow用户

发布于 2012-04-01 03:11:30

只需按那个地址

Process p = Runtime.getRuntime().exec("ping " + your_ip_address);

BufferedReader stdInput = new BufferedReader(new InputStreamReader(p.getInputStream()));