问当处理ajax和序列化数据时，php插入代码是什么样子的？

EN

$("#form").submit(function(event){
event.preventDefault();
var $form = $( this ),
url = $form.attr( 'action' );
var posting = $.post( url, {
id: $('#id').val(),
name: $('#name').val(),
wname: $('#wname').val(),
xcor: $('#xcor').val(),
ycor: $('#ycor').val(),
xwid: $('#xwid').val(),
yhei: $('#yhei').val(),
photo: $('#photo').val(),
targeturl: $('#targeturl').val()
});

posting.done(function( data ){
alert('success');
});
});

$("#form").submit(function(e){
var postData = $(this).seralizeArray();
var formURL = $(this).attr("action");
$.ajax({
url : formURL,
type : "POST",
data : postData
});
e.preventDefault();
e.unbind();
});
$("#form").submit();
alert('nice');

var frm = $('#form');
var formData = $('#form').serialize();
frm.submit(function (ev) {
$.ajax({
type: frm.attr('method'),
data: formData,
url: frm.attr('action'),
success: function (data) {
alert('successful update');
}
});
ev.preventDefault();
});

if($_SERVER['REQUEST_METHOD']=='POST'){

 $name = $_POST['name'];
 $email= $_POST['email'];

 $link = new mysqli("$servername", "$username", "$password", "$dbname");

 $stmt = mysqli_prepare($link, "INSERT INTO table VALUES(?,?)");
    $stmt->bind_param('ss',$name,$email);

        $stmt->execute();