我有一个场景来测试这样一个IOS应用程序:
我使用以下代码:
TouchAction action = new TouchAction(driver)
action.long_press(element1).move_to(element2).wait(500).release().perform()
但这不适合我。需要任何好的建议。
发布于 2016-03-18 04:40:09
我也因为这件事惹了麻烦。但我解决了这个问题如下:
TouchAction action = new TouchAction(driver);
action.longPress(elem1).waitAction(3000).moveTo(elem2).perform().release();
waitAction
将等待完成longPress
操作,然后moveTo
操作将执行。
发布于 2018-05-03 05:38:42
我发现没有一个longPress()组合可以工作,所以我使用了这个变体,您可以强制它执行按压,然后移动。在Android和iOS上测试,似乎不适用于UWP
new TouchAction(driver)
.press(PointOption.point(256, 1115))
.waitAction(WaitOptions.waitOptions(Duration.ofMillis(2000)))
.perform()
.moveTo(PointOption.point(256, 600))
.release()
.perform();
发布于 2020-05-17 23:50:30
//You need to import following
import org.openqa.selenium.WebElement;
import io.appium.java_client.TouchAction;
import io.appium.java_client.touch.LongPressOptions;
import io.appium.java_client.touch.offset.ElementOption;
//first for the intial location to be long pressed
WebElement first= driver.findElementByXPath("//*[@content-desc='15']");
//second location on which you need to move to
WebElement second= driver.findElementByXPath("//*[@content-desc='45']");
TouchAction action = new TouchAction(driver);
//performing the long press
action.longPress(new LongPressOptions().withElement(new
ElementOption().withElement(first))).perform();
//performing the move to touch operation
action.moveTo(new ElementOption().withElement(second)).perform();
https://stackoverflow.com/questions/36084388
复制相似问题