如何忽略Python中的"KeyError“
提问于 2020-05-23 21:44:26
我正在尝试使用api“yfinance”分析python中的股票。我让程序在大多数时候都运行得很好。但是，当它不能“找到”其中一个字段时，它将遍历一个错误(KeyError)。下面是我的代码片段。
import yfinance as yf
stock = yf.Ticker(stock)
pegRatio = stock.info['pegRatio']
print(pegRatio)
if pegRatio > 1:
print("The PEG Ratio for "+name+" is high, indicating that it may be overvalued (based on projected earnings growth).")
if pegRatio == 1:
print("The PEG Ratio for "+name+" is 1, indicating that it is close to fair value.")
if pegRatio < 1:
print("The PEG Ratio for "+name+" is low, indicating that it may be undervalued (based on projected earnings growth).")这是错误回溯(最近一次调用)：第29行，在行业=Stock.info‘行业’KeyError：‘行业’中。
我的主要问题是如何让代码基本上忽略错误并运行其余代码？
回答 1
Stack Overflow用户
发布于 2021-07-10 23:58:24
Python中的错误处理
就像Nicolas commented一样，你会在网上找到很多教程、博客文章和视频。还有一些基本的Python书籍，涵盖了“错误处理”。
Python中的控制结构至少由两个关键字try和except组成，它们通常被命名为try-except block。还有两个可选关键字else和finally。
如何包装失败的语句
import yfinance as yf
try: # st art watching for errors
stock = yf.Ticker(stock) # the API call may also fail, e.g. no connection
pegRatio = stock.info['pegRatio'] # here your actual exception was thrown
except KeyError: # catch unspecific or specific errors/exceptions
# handling this error type begins here: print and return
print "Error: Could not find PEG Ratio in Yahoo! Finance response!"
return
# the happy path continues here: with pegRatio
print(pegRatio)
if pegRatio > 1:
print("The PEG Ratio for "+name+" is high, indicating that it may be overvalued (based on projected earnings growth).")
if pegRatio == 1:
print("The PEG Ratio for "+name+" is 1, indicating that it is close to fair value.")
if pegRatio < 1:
print("The PEG Ratio for "+name+" is low, indicating that it may be undervalued (based on projected earnings growth).")页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/61978929
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