问如何从Android的窗口管理器中删除多个视图？
EN

Stack Overflow用户

提问于 2015-04-02 10:08:39

回答 1查看 2.4K关注 0票数 1

我正在处理来电显示应用程序，其中我在窗口管理器视图中显示所拨/接收号码的信息。用户可以手动关闭视图。一切都很顺利，直到我测试了它的呼叫等待服务。即使单击关闭按钮并显示错误"View Not Attached To Window Manager“，On call waiting视图仍会显示在屏幕上。我在服务中做了所有这些事情。

我的问题是，有没有办法一次点击就能删除多个视图。或者我可以跟踪附加到窗口管理器的视图。

这是我的代码

linearLayout = new LinearLayout(this);
    linearLayout.addView(textHeaderName);
    linearLayout.addView(textheader);
    linearLayout.addView(chatHead);
    linearLayout.addView(textfooter);
    linearLayout.setOrientation(LinearLayout.VERTICAL);

    btnClose.setImageResource(R.drawable.button_close);
    btnClose.setLeft(0);
    chatHead.setBackgroundResource(R.drawable.img);

android.view.WindowManager.LayoutParams layoutparams = new android.view.WindowManager.LayoutParams(WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.TYPE_PHONE,
            WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE,
            PixelFormat.TRANSPARENT);
    android.view.WindowManager.LayoutParams layoutparams1 = new android.view.WindowManager.LayoutParams(WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.TYPE_PHONE,
            WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE,
            PixelFormat.TRANSPARENT);
    android.view.WindowManager.LayoutParams layoutparams2 = new android.view.WindowManager.LayoutParams(WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.TYPE_PHONE,
            WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE,
            PixelFormat.TRANSPARENT);
    final android.view.WindowManager.LayoutParams paramsChatHead = new android.view.WindowManager.LayoutParams(WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.TYPE_PHONE,
            WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE,
            PixelFormat.TRANSPARENT);
    android.view.WindowManager.LayoutParams layoutparams3 = new android.view.WindowManager.LayoutParams(WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.WRAP_CONTENT,
            WindowManager.LayoutParams.TYPE_PHONE,
            WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE,
            PixelFormat.TRANSPARENT);

    new android.widget.LinearLayout.LayoutParams(WindowManager.LayoutParams.WRAP_CONTENT, WindowManager.LayoutParams.WRAP_CONTENT);

    layoutparams.gravity = 53;
    layoutparams.y = 0;
    layoutparams1.gravity = 49;
    layoutparams1.x = 0;
    layoutparams1.y = 0;
    layoutparams2.gravity = 49;
    layoutparams2.x = 0;
    layoutparams2.y = 25;
    paramsChatHead.gravity = 49;
    paramsChatHead.x = 0;
    paramsChatHead.y = 50;
    layoutparams3.gravity = 49;
    layoutparams3.x = 0;
    layoutparams3.y = imgheight + 50;

    try 
    {
        windowManager.addView(linearLayout, layoutparams1);
        windowManager.addView(btnClose, layoutparams);

    } catch (Exception e) 
    {}

关闭事件：

btnClose.setOnClickListener(new android.view.View.OnClickListener() 
    {
        public void onClick(View view)
        {
            try
            {
                if (linearLayout != null)
                {
                    windowManager.removeView(linearLayout);
                }
                if (btnClose != null)
                {
                    windowManager.removeView(btnClose);
                }
            } catch (Exception e) 
            {
                e.printStackTrace();
            }
        }     
    });

请帮帮忙

android

service

view

android-windowmanager

回答 1

Stack Overflow用户

发布于 2017-05-22 18:11:55

使用此条件：

 if (linearLayout.getWindowToken() != null) {
                                    windowManager.removeView(linearLayout);
                                }