我正在计算字符串中出现的字符数。我的代码如下:
data segment 'DSEG'
text db "This is a sentence.",0 ; string
textSize dw $ - text - 1 ; size of string, - 1 to account for null-termination character
freqTable dd 256 DUP(0)
ends 'DSEG'
code segment 'CSEG'
start:
mov ax, data ; set segment registers
mov ds, ax
mov es, ax
;---------------------------------------
sub cx, cx
mov cx, textSize ; number of times to loop
L1:
mov ax, [OFFSET text + cx - 1] ; loop from back using cx, put character in ax
inc [OFFSET freqTable + 4*ax] ; increment table's index at the ascii value of character
LOOP L1
;---------------------------------------
mov ax, 4c00h ; return to OS
int 21h
ends 'CSEG'
end start ; set entry point
我创建了一个DWORDS
数组,每个索引都表示一个字符。然后循环遍历字符串,并尝试在每个字符的ascii值处增加数组。
但是,当我试图在循环中增加时,我会得到一个wrong parameters
错误。我不知道是什么导致了这个错误。我猜我不能像我想要的那样增长。如何正确地创建频率表?我漏掉了什么小东西吗?
发布于 2015-05-21 13:06:07
为了帮助您理解如何计算我用EMU8086创建的下一个小程序(与您的程序集兼容)的字符数:该程序要求用户输入文件名,打开文件,读取所有字符并对它们进行计数,然后关闭文件。
下一张图片显示了它是如何工作的:有一个频率数组("freq_array"),有256个位置。每个位置是对应字符的计数器,例如,位置65是'A‘(chr(65))的计数器。
每次从文件中读取一个字符时,该字符本身被用作偏移量以到达其计数器。例如,如果从文件中读取char 48 ('0'),则将数字48添加到数组偏移量(偏移量+ 48)中,并且该位置将增加。当文件结束时,它的所有字符都已被计数。
现在代码:
.model small
.stack 100h
;-----------------------------------------
.data
freq_array dw 256 dup(0) ;ARRAY OF FREQUENCIES OF EACH ASCII CHARACTER.
msj db 13,10,'Enter name of file: $'
filename db 99 ;MAX NUMBER OF CHARACTERS ALLOWED (98).
db ? ;LENGTH (NUMBER OF CHARACTERS ENTERED BY USER).
db 99 dup(0) ;CHARACTERS ENTERED BY USER. END WITH CHR(13).
filehandler dw ? ;FILE HANDLER.
the_char db ? ;CHAR READ FROM FILE.
;-----------------------------------------
.code
start:
;INITIALIZE DATA SEGMENT.
mov ax, @data
mov ds, ax
call get_source_file ;GET FILE NAME.
call count_chars ;FILL FREQ_ARRAY WITH FREQUENCIES OF CHARS.
;WAIT FOR ANY KEY.
mov ah, 7
int 21h
;FINISH PROGRAM.
mov ax, 4c00h
int 21h
;-----------------------------------------
get_source_file proc
;DISPLAY MESSAGE.
mov dx, offset msj
mov ah, 9
int 21h
;CAPTURE FILENAME FROM KEYBOARD.
mov ah, 0Ah
mov dx, offset filename
int 21h
;CAPTURED STRING ENDS WITH CHR(13), BUT FILES REQUIRE
;THE FILENAME TO END WITH CHR(0), SO LET'S CHANGE IT.
mov si, offset filename + 1 ;STRING LENGTH.
mov cl, [ si ] ;MOVE LENGTH TO CL.
mov ch, 0 ;CLEAR CH TO USE CX.
inc cx ;ONE MORE BYTE TO REACH CHR(13).
add si, cx ;NOW SI POINTS TO CHR(13).
mov al, 0
mov [ si ], al ;REPLACE CHR(13) BY 0.
ret
get_source_file endp
;-----------------------------------------
;READ ALL CHARACTERS FROM FILE INCREASING THE COUNTER OF
;EACH CHARACTER IN THE ARRAY OF FREQUENCIES. EACH CHARACTER
;IS USED AS THE OFFSET OF ITS OWN COUNTER, EXAMPLE: THE
;COUNTER FOR 'A' IS THE POSITION 65 OF FREQ_ARRAY.
count_chars proc
;OPEN FILE.
mov ah, 3dh ;SERVICE TO OPEN FILE.
mov al, 0 ;OPEN AS READ ONLY.
mov dx, offset filename + 2
int 21h
mov filehandler, ax ;NECESSARY FOR OPERATIONS ON FILE.
;COUNT CHARACTERS.
reading:
;READ ONE CHAR FROM FILE.
mov ah, 3fh ;SERVICE TO READ FROM FILE.
mov bx, filehandler
mov cx, 1 ;HOW MANY BYTES TO READ.
mov dx, offset the_char ;WHERE TO STORE THE READ BYTES.
int 21h
;CHECK END OF FILE.
cmp ax, 0
je end_reading ;IF READ ZERO BYTES, FINISH.
;INCREASE COUNTER. THE CHAR ITSELF IS BEEN USED AS INDEX: THE
;COUNTER FOR CHAR 65 ('A') IS IN THE 65th POSITION OF THE ARRAY.
mov si, offset freq_array
mov al, the_char ;USE CHAR AS OFFSET OF ITS OWN COUNTER.
mov ah, 0 ;CLEAR AH TO USE AX.
shl ax, 1 ;AX * 2, BECAUSE EVERY COUNTER IS 2 BYTES.
add si, ax ;SI POINTS TO COUNTER POSITION.
inc [ word ptr si ] ;INCREMENT COUNTER FOR CURRENT CHAR.
jmp reading ;REPEAT PROCESS.
end_reading:
;CLOSE FILE.
mov ah, 3eh ;SERVICE TO CLOSE FILE.
mov bx, filehandler
int 21h
ret
count_chars endp
;-----------------------------------------
end start
希望这能帮到你。
这是16位,因为数组是DW。若要使其与32位(数组DD)兼容,请更改下一行:
freq_array dd 256 dup(0)
shl ax, 2 ;AX * 4, BECAUSE EVERY COUNTER IS 4 BYTES.
inc [ dword ptr si ] ;INCREMENT COUNTER FOR CURRENT CHAR.
发布于 2015-05-24 07:31:05
X86不允许像您一样通过使用AX和CX寄存器进行内存寻址。但是,您可以为此目的使用EAX和ECX。
下一个代码段zero 8,31和zero 16,31将保持为零。
;---------------------------------------
xor eax, eax
xor ecx, ecx
mov cx, textSize ; number of times to loop
L1:
mov al, [OFFSET text + ecx - 1]
inc [OFFSET freqTable + eax*4]
loop L1
;---------------------------------------
https://stackoverflow.com/questions/30383575
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