问Spring:如何使过滤器抛出自定义异常？
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Stack Overflow用户

提问于 2017-05-17 22:58:23

回答 3查看 17.2K关注 0票数 6

我创建了一个过滤器，对JWT令牌的每个请求头进行身份验证：

public class JWTAuthenticationFilter extends GenericFilterBean {

    private UserDetailsService customUserDetailsService;
    private static Logger logger = LoggerFactory.getLogger(JWTAuthenticationFilter.class);
    private final static UrlPathHelper urlPathHelper = new UrlPathHelper();

    public JWTAuthenticationFilter(UserDetailsService customUserDetailsService) {
        this.customUserDetailsService = customUserDetailsService;
    }

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain filterChain) throws IOException, ServletException {
        Authentication authentication = AuthenticationService.getAuthentication((HttpServletRequest) request, customUserDetailsService);
        SecurityContextHolder.getContext().setAuthentication(authentication);
        if (authentication == null) {
            logger.debug("failed authentication while attempting to access " + urlPathHelper.getPathWithinApplication((HttpServletRequest) request));
        }
        filterChain.doFilter(request, response);
    }

}

我想抛出一个自定义异常，该异常返回一个响应：

@ResponseStatus(value=HttpStatus.SOMECODE, reason="There was an issue with the provided authentacion information")  // 409
public class CustomAuthenticationException extends RuntimeException {

    private static final long serialVersionUID = 6699623945573914987L;

}

我该怎么做？捕捉过滤器抛出的这种异常的最佳设计是什么？Spring安全提供了什么类型的异常处理机制，我可以在一个点内使用和捕获所有的异常处理机制吗？是否有其他方法在筛选器中抛出自定义异常？

备注：还有另一个问题这里，它接受的答案没有回答我的问题。在到达任何控制器之前，我想返回一个响应。

我想要处理的错误情况: 1.客户端为授权头发送一个空值。2.客户端发送格式错误的令牌

在这两种情况下，我都会得到一个使用500 HTTP状态代码的响应。我要拿回4XX代码。

java

spring

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回答 3

Stack Overflow用户

发布于 2017-05-17 23:04:18

看看@ControllerAdvice

下面是我的项目的一个例子。

@ControllerAdvice
@RestController
public class GlobalExceptionHandler {

    private final Logger log = Logger.getLogger(this.getClass().getSimpleName());

    @ResponseStatus(HttpStatus.BAD_REQUEST)
    @ExceptionHandler(value = RuntimeException.class)
    public Response handleBaseException(RuntimeException e) {
        log.error("Error", e);
        Error error = new Error(HttpStatus.BAD_REQUEST.value(), HttpStatus.BAD_REQUEST.name());
        return Response.status(HttpStatus.BAD_REQUEST.value()).error(error, null).build();
    }

    @ResponseStatus(HttpStatus.NOT_FOUND)
    @ExceptionHandler(value = NoHandlerFoundException.class)
    public Response handleNoHandlerFoundException(Exception e) {
        log.error("Error", e);
        Error error = new Error(HttpStatus.NOT_FOUND.value(), HttpStatus.NOT_FOUND.name());
        return Response.status(HttpStatus.NOT_FOUND.value()).error(error, null).build();
    }

    @ExceptionHandler(value = AuthenticationCredentialsNotFoundException.class)
    public Response handleException(AuthenticationCredentialsNotFoundException e) {     
        log.error("Error", e);
        Error error = new Error(ErrorCodes.INVALID_CREDENTIALS_CODE, ErrorCodes.INVALID_CREDENTIALS_MSG);
        return Response.status(ErrorCodes.INVALID_CREDENTIALS_CODE).error(error, null).build();
    }

    @ResponseStatus(HttpStatus.UNAUTHORIZED)
    @ExceptionHandler(value = UnauthorisedException.class)
    public Response handleNotAuthorizedExceptionException(UnauthorisedException e) {        
//      log.error("Error", e);
        return Response.unauthorized().build();
    }

    @ExceptionHandler(value = Exception.class)
    public String handleException(Exception e) {
        log.error("Error", e);
        return e.getClass().getName() + " 14" + e.getMessage();
    }


}

编辑

我相信你可以在response.sendError里面做过滤方法。

@Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain filterChain) throws IOException, ServletException {
    Authentication authentication = AuthenticationService.getAuthentication((HttpServletRequest) request, customUserDetailsService);
    SecurityContextHolder.getContext().setAuthentication(authentication);
    if (authentication == null) {
        logger.debug("failed authentication while attempting to access " + urlPathHelper.getPathWithinApplication((HttpServletRequest) request));
        response.sendError(HttpServletResponse.SC_UNAUTHORIZED, "Invalid authentication.");
        setUnauthorizedResponse(response);
        return;
    }
    filterChain.doFilter(request, response);
}

public void setUnauthorizedResponse(HttpServletResponse response) {
    response.setStatus(HttpServletResponse.SC_UNAUTHORIZED);
    response.setContentType("application/json");
    Response unAuthorizedResponse = Response.unauthorized().build();
    try {
        PrintWriter out = response.getWriter();
        out.println(unAuthorizedResponse.toJsonString());
    } catch (IOException e) {
        log.error("Error", e);
    }
}

票数 4

Stack Overflow用户

发布于 2017-09-21 12:59:03

我对JWT令牌也有同样的问题，并在这个问题上发布了解决方案，因为这个问题类似(他在过滤器异常方面有问题)。

票数 0

Stack Overflow用户

发布于 2021-07-06 22:29:54

免责声明:这不是问题的答案，但这是对Arian提出的问题的后续回答。

如上文所述，在春季容器允许我们访问bean之前，您可以在这些地方进行自动测试。

在这里，我正在自动完成我的BlacklistJwtRepo

if (blacklistJwtRepo == null) { //Lazy Load because filter
        ServletContext servletContext = req.getServletContext();
        WebApplicationContext webApplicationContext =  WebApplicationContextUtils.getWebApplicationContext(servletContext);
        blacklistJwtRepo = webApplicationContext.getBean(BlacklistJwtRepo.class);
    }

我在这里找到了req对象-

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
    HttpServletRequest req = (HttpServletRequest) request;

最后的代码看起来-

    @Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain)
        throws IOException, ServletException {
    HttpServletRequest req = (HttpServletRequest) request;      
    System.out.println("blacklistJwtRepo : " + blacklistJwtRepo);
    //till here the autowired repo (blacklistJwtRepo) is null
    if (blacklistJwtRepo == null) { //Lazy Load because filter
        ServletContext servletContext = req.getServletContext();
        WebApplicationContext webApplicationContext = WebApplicationContextUtils.getWebApplicationContext(servletContext);
        blacklistJwtRepo = webApplicationContext.getBean(BlacklistJwtRepo.class);
    }