问向.executemany提供DataFrame值以进行更新
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Stack Overflow用户

提问于 2020-08-14 20:17:33

回答 1查看 374关注 0票数 2

我需要通过python在MSSQL中更新excel数据。因此，首先我读取excel文件(其中只有一行)并对数据类型进行必要的更改：

import pyodbc 
import pandas as pd
df = pd.read_excel('test_new.xlsx')
first_col = df.pop('number')
df['number'] = first_col
df['sys_created_on'] = df['sys_created_on'].dt.strftime('%Y-%m-%d %H:%M:%S')
df['opened_at'] = df['opened_at'].dt.strftime('%Y-%m-%d %H:%M:%S')
df['resolved_at'] = df['resolved_at'].dt.strftime('%Y-%m-%d %H:%M:%S')
df['sys_updated_on'] = df['sys_updated_on'].dt.strftime('%Y-%m-%d %H:%M:%S')
df.fillna('', inplace=True)
records = df.to_records(index=False)
result = list(records)
result

上面的语句给出了结果。结果是一个列表

[('Sha', 'po1301', 'Closed', 'TLS - Admin', 15585, 'Store Network', 'Switch', 'CATS0005587', '', 'mic.vin.com ', 'pis - opo', 'LEC NIN', '2020-08-11 23:56:03', '1 Pro 1 LLC', '', '', 'Switch', '', '', '', 'Phone', 'oshi3001', 'Resolved', '"Approved Tech\r\n1. troubleshooting.\r\n"\r\n\r\n\r\nIMPORTANT - TECH SHOULD CALL NOC ON ARRIVAL', 'No', False, '1 - High', '0-6 hours', False, 'mada gill', '7-ELEVEN STORE - 38578', '', '2020-08-11 23:56:03', 'john win', '1 - Critical', 6, '', 'Not Solved (Not Reproducible)', 'duplicate case, see notes', 59022, '2020-08-12 16:19:45', '', 'UNKNOWN', '3 - Low', 'Store is hard down', 1, 'Power Verification', 'svd', '1 - High', '2020-08-12 16:19:45', False, 'INC1090099')]

在这部分之后，我创建了一条SQL update语句：

conn = pyodbc.connect()
cursor = conn.cursor()
cursor.executemany("Update proj.[mid].[datahub] SET assigned_to = ?, [caller_id#user_name] = ?, state = ?, assignment_group = ?, business_duration = ?, business_service = ?, category = ?, u_category_structure = ?, u_resolution_ci = ?, resolved_by = ?, u_resolver_group = ?, u_service_provider = ?, sys_created_on = ?, caller_id = ?, u_caller_first_name = ?, u_caller_last_name = ?, u_vendor_category = ?, rfc = ?, closed_at = ?, closed_by = ?, contact_type = ?, sys_created_by = ?, u_customer_portal_state = ?, description = ?, u_first_call_resolution = ?, u_first_time_fix = ?, impact = ?, u_incident_age = ?, knowledge = ?, reopened_by = ?, location = ?, u_on_behalf_of = ?, opened_at = ?, opened_by = ?, priority = ?, reassignment_count = ?, u_resolution_method = ?, close_code = ?, close_notes = ?, calendar_stc = ?, resolved_at = ?, u_sd_esclation = ?, sla_due = ?, severity = ?, short_description = ?, reopen_count = ?, subcategory = ?, sys_updated_by = ?, urgency = ?, sys_updated_on = ?, [assigned_to#active] = ? WHERE number = ?", result)
cursor.commit()

它给出了错误: ProgrammingError:执行的第二个参数必须是序列、迭代器或生成器。

由于某些原因，它并不将结果变量作为列表，而实际上它是一个列表。如果我在cursor.executemany()中打印语句，然后执行它，它会更新数据，但是使用保存列表的result变量，它不能工作。

请帮帮忙。

python

sql-server

pandas

dataframe

pyodbc

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回答 1

Stack Overflow用户

回答已采纳

发布于 2020-08-14 22:48:58

result = print(list(tuple(records)))

将结果打印到控制台，但print函数本身返回None。相反，您应该省略records调用，并像这样分配result ...

result = list(df.itertuples(index=False))

..。如果你愿意，那就把它打印出来

print(result)

编辑:完整的工作示例

cnxn = pyodbc.connect("DSN=mssqlLocal64")
crsr = cnxn.cursor()

# set up test environment
crsr.execute("CREATE TABLE #tmp (txt varchar(10), id int primary key)")
crsr.execute(
    "INSERT INTO #tmp (txt, id) VALUES "
    "('old_foo', 1), ('old_bar', 2)"
)
print(crsr.execute("SELECT * FROM #tmp").fetchall())
"""console output:
[('old_foo', 1), ('old_bar', 2)]
"""

# test
df = pd.DataFrame([("new_foo", 1), ("new_bar", 2)], columns=["txt", "id"])
result = list(df.itertuples(index=False))
crsr.executemany("UPDATE #tmp SET txt = ? WHERE id = ?", result)
print(crsr.execute("SELECT * FROM #tmp").fetchall())
"""console output:
[('new_foo', 1), ('new_bar', 2)]
"""