问跟踪海龟的位置，让另一只乌龟去那里
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Stack Overflow用户

提问于 2020-05-18 16:38:01

回答 2查看 265关注 0票数 1

我正在使用海龟模块的Python，我试图做一个游戏。我正试着让一只乌龟射出另一只乌龟作为子弹。我想不出如何追踪射击龟的xcor()和ycor()，然后再把子弹龟运到那里。这是我的代码：

# Projectiles

bullet = turtle.Turtle()
bullet.hideturtle()
bullet.color('purple')
bullet.shape('circle')
bullet.penup()
bullet.shapesize(0.5, 0.5)

bulletspeed = 0


# The player  

player = turtle.Turtle()
player.speed(0)
player.color('blue')
player.shape('triangle')
player.penup()
player.setposition(0, -250)
player.setheading(90)

x = player.xcor()
y = player.ycor()
ph = player.heading()

def right():
    player.right(30) 

def left():
    player.left(30)

def increasespeed():
    global speed
    speed += 1

def decreasespeed():
    global speed
    speed -= 1

def bulletmove():
    global bulletspeed
    bullet.pos() == player.pos()
    bullet.showturtle()
    bulletspeed += 10


# Keybindings

turtle.listen()
turtle.onkey(left, 'Left')
turtle.onkey(right, 'Right')
turtle.onkey(increasespeed, 'Up')
turtle.onkey(decreasespeed, 'Down')
turtle.onkey(bulletmove, 'space')

python

python-turtle

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回答 2

Stack Overflow用户

发布于 2020-05-18 20:50:59

在这里，我完全修改了你的代码。这仍然是一个小问题，但这是因为turtle模块本身。我不得不让球员掉头，但这很有效。

import turtle

# Projectiles

bullet = turtle.Turtle()

bullet.color('purple')
bullet.penup()
bullet.speed("fastest")
bullet.hideturtle()
bullet.shape("circle")

bullet.setposition(0, -250)



bulletspeed = 0

s = turtle.Screen()
# The player  


player = turtle.Turtle()
player.speed("fastest")
player.color('blue')
player.shape('triangle')
player.penup()
player.setposition(0, 0)
player.setheading(90)
#player.hideturtle()
x = player.xcor()
y = player.ycor()
ph = player.heading()
player.right(180)

speed = 5

def right():
    player.right(30) 

def left():
    player.left(30)

def increasespeed():
    global speed
    speed += 1

def decreasespeed():
    global speed
    speed -= 1


def bulletmove():
    global bulletspeed
    bullet.hideturtle()
    turtlex = 0
    turtley = -250
    bullet.setposition(turtlex, turtley)

    bullet.reset()
    bullet.penup()

    bullet.goto(0, -250)




# Keybindings

turtle.listen()
turtle.onkey(left, 'Left')
turtle.onkey(right, 'Right')
turtle.onkey(increasespeed, 'Up')
turtle.onkey(decreasespeed, 'Down')
turtle.onkey(bulletmove, 'space')

#s.tracer(0, 0)
s.exitonclick()

另外，我建议用一颗移动的子弹来做一个游戏，使用海龟是不可取的。我建议吡咯。

希望这能有所帮助！

票数 0

Stack Overflow用户

发布于 2020-05-18 21:53:36

不要相信试图在另一个图书馆卖给你的人给你的一个海龟例子。我并不是说游戏对这类程序没什么好处，只是海龟的能力经常被低估。

下面是你的代码重写，允许你旋转和射击-多个子弹在一次！为了保持示例的简单性，我抛出了您的增减速度功能：

from turtle import Screen, Turtle

def right():
    player.right(30)
    screen.update()

def left():
    player.left(30)
    screen.update()

def move_bullet(bullet):
    screen.onkey(None, 'space')  # disable handler inside handler

    if bullet.distance(player) < 300:
        bullet.forward(10)
        screen.ontimer(lambda: move_bullet(bullet), 100)
    else:
        bullet.hideturtle()
        bullets.append(bullet)  # reduce, reuse & recycle

    screen.update()
    screen.onkey(fire_bullet, 'space')  # reenable handler

def fire_bullet():
    bullet = bullets.pop() if bullets else bullet_prototype.clone()

    bullet.setposition(player.position())
    bullet.setheading(player.heading())
    bullet.showturtle()

    move_bullet(bullet)

screen = Screen()
screen.tracer(False)

bullet_prototype = Turtle()
bullet_prototype.hideturtle()
bullet_prototype.shape('circle')
bullet_prototype.shapesize(0.5)
bullet_prototype.color('purple')
bullet_prototype.penup()

bullets = []

player = Turtle()
player.shape('triangle')
player.color('blue')
player.penup()
player.setheading(90)

screen.onkey(left, 'Left')
screen.onkey(right, 'Right')
screen.onkey(fire_bullet, 'space')
screen.listen()

screen.update()
screen.mainloop()