问用多天解析日期字符串

EN

import re

date1 = "March 20 & June 8, 2011"
date2 = "September 4 & 27, 2010"
date3 = "February 15, December 5 & 6, 2013"
date_group = [date1,date2,date3]

for date in date_group:
    result = re.findall(r"\d{4}|[A-Z][a-z]+ \d{1,2} & \d{1,2}|[A-Z][a-z]+ \d{1,2}", date)
    year = result[-1]
    for i in range(len(result)-1):
        d = result[i].split(" ")
        try:
            d.remove("&")
        except ValueError:
            pass
        finally:
            for a in range(1,len(d)):
                date = d[0]+'{:02d}'.format(int(d[a]))+year
                time_date = datetime.strptime(date,"%B%d%Y")
                print (time_date)

2011-03-20 00:00:00
2011-06-08 00:00:00
2010-09-04 00:00:00
2010-09-27 00:00:00
2013-02-15 00:00:00
2013-12-05 00:00:00
2013-12-06 00:00:00

import datetime
d1 = "March 20 & June 8, 2011"
d2 = "February 15, December 5 & 6, 2013"


def getDate(in_value):
    result = []
    in_value = in_value.split(",")
    year = in_value.pop(-1)
    for dateV in in_value:
        if "&" in dateV:
            temp = []
            val = dateV.split()
            month = val.pop(0)
            for i in val:
                if i.isdigit():
                    temp.append(datetime.datetime.strptime("{}-{}-{}".format(year, month, i).strip(), "%Y-%B-%d").strftime("%m/%d/%Y"))
            result.append(" & ".join(temp))
        else:
            result.append(datetime.datetime.strptime(dateV.strip() + year, "%B %d %Y").strftime("%m/%d/%Y"))
    return ", ".join(result)

print( getDate(d1) )    
print( getDate(d2) )

03/20/2011 & 03/08/2011
02/15/2013, 12/05/2013 & 12/06/2013

import re
def split_date(d):
    return re.split(‘[,|&]’, d)