如何在spark中反规范化JSON
如何在spark中反规范化JSON
提问于 2018-05-14 19:34:37
例如，假设这是JSON，如下所示。我实际上是从亚马逊网站上拿来的，但我认为这适用于这个问题。
{
"player": {
"username": "user1",
"characteristics": {
"race": "Human",
"class": "Warlock",
"subclass": "Dawnblade",
"power": 300,
"playercountry": "USA"
},
"arsenal": {
"kinetic": {
"name": "Sweet Business",
"type": "Auto Rifle",
"power": 300,
"element": "Kinetic"
},
"energy": {
"name": "MIDA Mini-Tool",
"type": "Submachine Gun",
"power": 300,
"element": "Solar"
},
"power": {
"name": "Play of the Game",
"type": "Grenade Launcher",
"power": 300,
"element": "Arc"
}
},
"armor": {
"head": "Eye of Another World",
"arms": "Philomath Gloves",
"chest": "Philomath Robes",
"leg": "Philomath Boots",
"classitem": "Philomath Bond"
},
"location": {
"map": "Titan",
"waypoint": "The Rig"
}
}
} 我想把这个转换成下面的，并保存为avro。我是spark编程的新手，所以在java背景下，对函数式风格的理解是有点困难的。请至少引导我，让我可以自己写代码。
{
"player.username": "user1",
"player.characteristics.race": "Human",
"player.characteristics.class": "Warlock",
"player.characteristics.subclass": "Dawnblade",
"player.characteristics.power": 300,
"player.characteristics.playercountry": "USA",
"player.arsenal.kinetic.name": "Sweet Business",
"player.arsenal.kinetic.type": "Auto Rifle",
"player.arsenal.kinetic.power": 300,
"player.arsenal.kinetic.element": "Kinetic",
"player.arsenal.energy.name": "MIDA Mini-Tool",
"player.arsenal.energy.type": "Submachine Gun",
"player.arsenal.energy.power": 300,
"player.arsenal.energy.element": "Solar",
"player.arsenal.power.name": "Play of the Game",
"player.arsenal.power.type": "Grenade Launcher",
"player.arsenal.power.power": 300,
"player.arsenal.power.element": "Arc",
"player.armor.head": "Eye of Another World",
"player.armor.arms": "Philomath Gloves",
"player.armor.chest": "Philomath Robes",
"player.armor.leg": "Philomath Boots",
"player.armor.classitem": "Philomath Bond",
"player.location.map": "Titan",
"player.location.waypoint": "The Rig"
}回答 1
Stack Overflow用户
发布于 2018-05-15 02:06:35
它实际上与spark无关，您只需要一个函数来将嵌套的json字符串展平为一个新的json字符串。如果您先使用RDDString，则代码示例将是某种东西。
rdd.mapPartitions(ps => ps.map(jsonFlatten)) 然后将rdd转换为dataframe
示例jsonFlatten可以从以下位置找到：
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50337764
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