问有没有一种干净的方法将lua表(作为字符串)转换为javascript数组？(反之亦然)
EN

Stack Overflow用户

提问于 2019-09-25 20:07:31

回答 3查看 871关注 0票数 0

编辑:将lua表作为字符串，并使用javascript将其转换为javascript数组。在lua中没有编程。

因此，lua表只是一个不同格式的关联数组。

    --LUA TABLE EXAMPLE
    {
    ["glow"] = true,
    ["xOffset"] = -287.99981689453,
    ["yOffset"] = -227.55575561523,
    ["anchorPoint"] = "CENTER",
    ["cooldownSwipe"] = true,
    ["customTextUpdate"] = "update",
    ["cooldownEdge"] = false,
    ["icon"] = true,
    ["useglowColor"] = false,
    ["internalVersion"] = 24,
    ["keepAspectRatio"] = false,
    ["animation"] = {
        ["start"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
        ["main"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
        ["finish"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
    }

我四处寻找了一些javascript函数或库来实现这一点，尽管我只遇到了一些lua库来将json转换为lua表。lua表总是在一个字符串中。有没有办法做到这一点？

javascript

arrays

lua

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回答 3

Stack Overflow用户

发布于 2019-09-25 20:19:10

您可以手动将其设置为有效的JSON，然后对其进行解析：

const luaStr = `{
    ["glow"] = true,
    ["xOffset"] = -287.99981689453,
    ["yOffset"] = -227.55575561523,
    ["anchorPoint"] = "CENTER",
    ["cooldownSwipe"] = true,
    ["customTextUpdate"] = "update",
    ["cooldownEdge"] = false,
    ["icon"] = true,
    ["useglowColor"] = false,
    ["internalVersion"] = 24,
    ["keepAspectRatio"] = false,
    ["animation"] = {
        ["start"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
        ["main"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
        ["finish"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
    }}`;

const result = luaStr  
  .replace(/\[|\]/g, '') // remove the brackets
  .replace(/=/g, ':') // replace the = with :
  .replace(/(\,)(?=\s*})/g, ''); // remove trailing commas
  
const parsed = JSON.parse(result);

console.log(result);

票数 1

Stack Overflow用户

发布于 2019-09-25 20:45:33

这只是一个部分的解决方案。在字符串中的文本与键语法匹配的某些情况下，它可能会失败。但这可能不是你关心的问题。

const lua = `
{
    ["glow"] = true,
    ["xOffset"] = -287.99981689453,
    ["yOffset"] = -227.55575561523,
    ["anchorPoint"] = "CENTER",
    ["cooldownSwipe"] = true,
    ["customTextUpdate"] = "update",
    ["cooldownEdge"] = false,
    ["icon"] = true,
    ["useglowColor"] = false,
    ["internalVersion"] = 24,
    ["keepAspectRatio"] = false,
    ["animation"] = {
        ["start"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
        ["main"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
        ["finish"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
    }
}`

const lua2json = lua => 
  JSON .parse (lua .replace (
    /\[([^\[\]]+)\]\s*=/g, 
    (s, k) => `${k} :`
  ) 
  .replace (/,(\s*)\}/gm, (s, k) => `${k}}`))

console .log (
  lua2json (lua)
)

我不知道您是想创建JSON还是一个对象。我选择了后者，但是您可以随时删除JSON.parse包装器。

票数 1

Stack Overflow用户

发布于 2019-09-25 20:39:52

这里有一些你可能不知道的东西，{ ["someString"]: 2 }是有效的javascript，它的计算结果是{someString: 2}，这是有效的json。唯一的问题是它需要被评估，这意味着使用eval (如果你可以避免的话，你真的永远不应该这样做)。

const luaStr = `{
    ["glow"] = true,
    ["xOffset"] = -287.99981689453,
    ["yOffset"] = -227.55575561523,
    ["anchorPoint"] = "CENTER",
    ["cooldownSwipe"] = true,
    ["customTextUpdate"] = "update",
    ["cooldownEdge"] = false,
    ["icon"] = true,
    ["useglowColor"] = false,
    ["internalVersion"] = 24,
    ["keepAspectRatio"] = false,
    ["animation"] = {
        ["start"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
        ["main"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
        ["finish"] = {
            ["duration_type"] = "seconds",
            ["type"] = "none",
        },
    }}`;
    
const jsonString = luaStr.replace(/\] = /g, ']: ');
const jsonObj = eval(`(${jsonString})`);

console.log(jsonObj);