如何从ggplot2 R中的自举模型中绘制具有估计平均值和置信区间的原始数据点？
提问于 2019-07-22 19:31:21
我有几个因素的数据。我运行了一个带有均值和置信区间的自举模型。我想绘制两个数据点以及模型结果均值和置信区间。我怎样才能做到这一点呢？
yval <- c(0.10,0.12,0.50,0.13,0.20,0.15,0.68,0.71,0.90,0.10,0.11,0.12,0.14,0.15,0.16,0.20,0.14,0.15,0.66,0.222)
type <- c("A","S","A","S","A","S","A","S","A","S","A","S","A","S","A","S","A","S","A","S")
status <- c("L","H","L","H","L","H","L","H","L","H","L","H","L","H","L","H","L","H","L","H")
data <- data.frame(yval, type, status)然后我尝试了一个很长很复杂的模型，它给出了这个矩阵
est 2.5% 97.5%
(Intercept) 0.14593333 -0.10347804 0.3817681
typeA 0.26295217 -0.01156827 0.5503199
statusH 0.09181279 -0.18906489 0.3748384我希望将原始数据绘制为模型中具有适当平均值和置信区间的点。请不要建议在ggplot2中使用内置引导置信区间。我想特别使用上面的几个。
ggplot(data, aes(x=status, y= yval, color = status)) + theme_bw() + geom_point(position = pd, size = 1.5) + facet_grid(.~type)
回答 1
Stack Overflow用户
回答已采纳
发布于 2019-07-22 20:03:41
你在找geom_errorbar吗？
data2<-data.frame(yval= c(0.10,0.12,0.50,0.13,0.20,0.15,0.68,0.71,0.90,0.10,0.11,0.12,0.14,0.15,0.16,0.20,0.14,0.15,0.66,0.222),
typeA =c("A","S","A","S","A","S","A","S","A","S","A","S","A","S","A","S","A","S","A","S"),
statusH=c("L","H","L","H","L","H","L","H","L","H","L","H","L","H","L","H","L","H","L","H")
)
data2<-data2%>%
mutate(.,type=mapvalues(data2$type, from = c("A", "S"), to = c("typeA", "statusH")))
data<-read.table(text="
type est l2.5 u97.5
(Intercept) 0.14593333 -0.10347804 0.3817681
typeA 0.26295217 -0.01156827 0.5503199
statusH 0.09181279 -0.18906489 0.3748384
",header=T)
pd=position_dodge(10)
ggplot(data, aes(x=type, y= est, color = type)) +
theme_bw() +
geom_point(size = 3.5,position=pd) +
geom_errorbar(aes(ymin=l2.5, ymax=est+u97.5), width=0.1,position = pd)+
geom_point(data=data2, aes(x=type,y=yval),size=1)我可能遗漏了一些东西，但听起来你可以直接使用第二个矩阵。
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https://stackoverflow.com/questions/57152612
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